X^2-104x+2535=0

Solution for X^2-104x+2535=0 equation:

X^2-104X+2535=0

a = 1; b = -104; c = +2535;
Δ = b2-4ac
Δ = -1042-4·1·2535
Δ = 676
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{676}=26$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-104)-26}{2*1}=\frac{78}{2}
=39
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-104)+26}{2*1}=\frac{130}{2}
=65
$